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*To*: tesla-at-pupman-dot-com*Subject*: Re: High Voltage Output*From*: "Tesla list" <tesla-at-pupman-dot-com>*Date*: Tue, 01 Jun 2004 17:22:45 -0600*Resent-Date*: Tue, 1 Jun 2004 17:26:21 -0600*Resent-From*: tesla-at-pupman-dot-com*Resent-Message-ID*: <0-zQ8B.A.iTG.OCRvAB-at-poodle>*Resent-Sender*: tesla-request-at-pupman-dot-com

Original poster: "Antonio Carlos M. de Queiroz" <acmdq-at-uol-dot-com.br> Tesla list wrote: > > Original poster: "Chris Fanjoy" <zappyman-at-hotmail-dot-com> > > As someone relatively new to this hobby (still building my first TC) I > haven't fully grasped all the principles involved. One thing that has me > puzzled is this: what determines the high voltage output of a Tesla coil? > If not the step-up ratio of the coil itself, then how about: > -Firing rate of spark gap > -Size of tank capacitor > -Operating frequency of coil > -All of the above? > Just curious, as this may be something to consider as I design my own TC. Essentially, the ratio of the primary capacitance to the secondary (distributed) capacitance. A classical Tesla coil is a pair of coupled LC tanks tuned to the same frequency, one, the primary, with low impedance, and another, the secondary, with high impedance. When some energy is put in the primary, causing it to oscillate, the oscillations gradually transfer the energy to the secondary, and after some cycles all (or almost, allowing for losses) of it can be transferred. Considering that the initial energy is in the primary capacitor C1 and the maximum output voltage occurs if all the initial energy ends in the secondary capacitance C2, the ideal voltage gain is sqrt(C1/C2). The energy transfer tends to revert direction after it is complete, returning the energy to the primary tank in the same number of cycles, and the sequence repeats. It happens, however, that eventually the primary gap ceases to conduct at one of the times when all the energy is in the secondary system ("quenches"), and after this the remaining energy is trapped in the secondary system until complete dissipation. Curiously, as both tanks are tuned to the same frequency, and so L1*C1=L2*C2, the gain is also equal to sqrt(L2/L1). If both coils could be wound with the same geometry, this would be precisely the turns ratio between the coils. Antonio Carlos M. de Queiroz

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