A = 0.99999...
10A = 9.99999...
10A - A = 9
9A = 9
A = 1
0.99999... = 1
2+2=5 for sufficiently large values of 2.
...A mathematician is a person who says that, when 3 people are supposed to be in a room but 5 came out, 2 more have to go in so the room gets empty...
[ QUOTE ]
Why cant dividing with zero be infinity?
[/ QUOTE ]
It is but infinity is not a valid return value in most programming languages and even where it is all further operations on the result return NaN (not a number) which means if you wanted to do something important with that number you can just as well throw a fatal exception now.
[ QUOTE ]
A = 0.99999...
10A = 9.99999...
10A - A = 9
9A = 9
A = 1
0.99999... = 1
[/ QUOTE ]
Well, yes, a period after the decimal point is supposed to have a digit that's one larger than the others after an infinite number of the periodic digit. An infinite number of 9s and a number that's 1 larger than 9 in the end (10) would mean that each 9 gets one added as the previous receives one carry, goes to 0 and throws a new carry. 0.9999999... is defined as 1.
Replies
Hail 1.
May Hexadecimal himself forgive you and bless you.
May Hexadecimal herself forgive you and bless you.
[/ QUOTE ]
OOHHHH SHIIITTTT
in other news.... DIVISION BY ZERO POSSIBLE http://www.bbc.co.uk/berkshire/content/articles/2006/12/06/divide_zero_feature.shtml
Discuss.
Why cant dividing with zero be infinity?
[/ QUOTE ]something like 2/0=infinite and 15/0=infinite so 2=15 :P
[ QUOTE ]
Why cant dividing with zero be infinity?
[/ QUOTE ]something like 2/0=infinite and 15/0=infinite so 2=15 :P
[/ QUOTE ]
Someone should mark this thread...
lim
x->2
(x^2-5x+6)/(x^2-6x+8)
who can figure out how to not divide by zero?
x->2
lim f(x) = (x-3) ÷ (x-4)
x->2
lim f(x) = 1/2
x->2
This is the first time I've seen a thread descend into algebra...
[/ QUOTE ]
calculus
This is the first time I've seen a thread descend into algebra...
[/ QUOTE ]
obviously you've never been to gamedev.net. get a forum of mostly programmers together and this occurs quite often.
So, it's well over my head. :P
I suxz0rs to the max at math.
-caseyjones
I'm in a speshul math class in highschool. LOwest of the low. The teacher talks really slow...
heheh
lim
x->2
(x^2-5x+6)/(x^2-6x+8)
[/ QUOTE ]
Better with x->4
A = 0.99999...
10A = 9.99999...
10A - A = 9
9A = 9
A = 1
0.99999... = 1
2+2=5 for sufficiently large values of 2.
...A mathematician is a person who says that, when 3 people are supposed to be in a room but 5 came out, 2 more have to go in so the room gets empty...
im in my thread, hyjacking my thread.
If you're creative in math, you'll make your teacher smile, and maybe even start liking you
[/ QUOTE ]
Or this one.
"Schoolchildren are among the first to learn the solution to a 1200 year-old problem: dividing by zero."
lol
http://www.gamedev.net/community/forums/topic.asp?topic_id=427411
Why cant dividing with zero be infinity?
[/ QUOTE ]
It is but infinity is not a valid return value in most programming languages and even where it is all further operations on the result return NaN (not a number) which means if you wanted to do something important with that number you can just as well throw a fatal exception now.
[ QUOTE ]
A = 0.99999...
10A = 9.99999...
10A - A = 9
9A = 9
A = 1
0.99999... = 1
[/ QUOTE ]
Well, yes, a period after the decimal point is supposed to have a digit that's one larger than the others after an infinite number of the periodic digit. An infinite number of 9s and a number that's 1 larger than 9 in the end (10) would mean that each 9 gets one added as the previous receives one carry, goes to 0 and throws a new carry. 0.9999999... is defined as 1.
[/ QUOTE ]
HAHAHAHAHAHAHAHA!
You weren't meant to share our private conversations... GEEZ!
-caseyjones